If it's not what You are looking for type in the equation solver your own equation and let us solve it.
24x^2+10x-6=0
a = 24; b = 10; c = -6;
Δ = b2-4ac
Δ = 102-4·24·(-6)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-26}{2*24}=\frac{-36}{48} =-3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+26}{2*24}=\frac{16}{48} =1/3 $
| 17x-83=110x-31x+100 | | 2n+37=5n+16 | | -1/8(x+35)=−7 | | 100/m=20 | | (x+0.05x)-500=(x-0.08x)-1000 | | 5x+10=(2x×2x)+x | | (5x+2)=(4x+6) | | 2x+14=x-4 | | (60+30)x=(350)30x | | 6p-2-3p2=16 | | 10w-30=50 | | (x+1)^2-x^2=17 | | 7(x-3)+14=14 | | 4a-5a=6 | | 7/y^2-144=(y+12)(y-12) | | 5x+10=(2 | | x=2(180-x)-20 | | x=4x-86 | | 34+16-15x=32+83x | | v6– -21= 25 | | t^2=(1)^2=(2)^2 | | 5z=3(z-6) | | 9y-13=-61+y | | (67+25x)x=300+25x | | 8.x+x=54 | | 4y-12=4y-6-2 | | 4b+5=4b-5 | | 12=5+w/2 | | 1/6v+17=-24 | | 8xX+X=54 | | -x-8=-4x-23 | | (67+25)x=300+20x |